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LESSON PLAN

Multiplication and Division of Decimals

A
Apothem Team
Grade 6 · Computational Fluency
LESSON AT A GLANCE
Warm-up
5 min
Explore
15 min
Formalize
10 min
Practice
12 min
Exit ticket
3 min

Warm-up

Hold up a store flyer: "Granola bars, $0.85 each. I'm buying 6." Ask for the total by mental math and collect strategies: some do 6×856 \times 85 cents =510= 510 cents =$5.10= \$5.10; some do 6×0.8+6×0.056\times0.8 + 6\times0.05. Both work — and both dodge the decimal until the end or split it sensibly.

Name the theme of the unit: decimal multiplication and division are whole-number operations plus PLACE-VALUE bookkeeping. The digits do what they always did; only the point needs managing.

Explore

Estimation-first workshop: for each of 4.2×0.54.2 \times 0.5, 0.3×0.40.3 \times 0.4, 6.4÷0.86.4 \div 0.8, pairs first bracket the answer ("more or less than 4.2? than 1?"), then compute with any method (grids, money, repeated reasoning), then reconcile.

The two shockers to let land: multiplying by a number less than 1 SHRINKS (0.3×0.4=0.120.3 \times 0.4 = 0.12 — smaller than both factors), and dividing by a number less than 1 GROWS (6.4÷0.8=86.4 \div 0.8 = 8). The 10×10 grid shows why: 0.3 of 0.4 is a sliver of a sliver.

Formalize

Formalize both operations through whole-number arithmetic. Multiplication: multiply as whole numbers, then place the point so the answer has as many decimal places as the factors combined — because each factor was scaled by a power of ten:

3.6×0.24=36×2410×100=8641000=0.8643.6 \times 0.24 = \frac{36 \times 24}{10 \times 100} = \frac{864}{1000} = 0.864

Division: shift BOTH numbers' points until the divisor is whole (6.4÷0.864÷86.4 \div 0.8 \to 64 \div 8) — legal because both scaled by the same factor, and a quotient is unchanged when both numbers grow tenfold. Then divide as usual. The estimate made first referees the point's final position.

Practice

Practice: six computations mixed with three estimation-only items ("is 0.9×520.9 \times 52 closer to 5, 50, or 500?"), one money problem, and one "place the point" puzzle where the digits 336 are given and students must position points to make 4.8×0.7=?4.8 \times 0.7 = ? true.

Exit ticket: compute 0.6×0.350.6 \times 0.35 AND explain with the grid or the fraction form why the answer is smaller than both factors.

Exit ticket

Practice: six computations mixed with three estimation-only items ("is 0.9×520.9 \times 52 closer to 5, 50, or 500?"), one money problem, and one "place the point" puzzle where the digits 336 are given and students must position points to make 4.8×0.7=?4.8 \times 0.7 = ? true.

Exit ticket: compute 0.6×0.350.6 \times 0.35 AND explain with the grid or the fraction form why the answer is smaller than both factors.

TIP  Never let "count the decimal places" live without its reason (the powers of ten underneath). Rule-only students place points confidently and wrongly the first time a trailing zero appears (2.5×0.4=1.002.5 \times 0.4 = 1.00).
WORKED EXAMPLES
Example 1 — 2.7×3.42.7 \times 3.4 with an estimate riding shotgun

Step 1: Estimate: 2.732.7 \approx 3 and 3.43.53.4 \approx 3.5 → about 1010 (a bit under, since 2.7 rounded up more than 3.4).

Step 2: Multiply as whole numbers: 27×34=27×30+27×4=810+108=91827 \times 34 = 27\times30 + 27\times4 = 810 + 108 = 918.

Step 3: Place the point: one decimal place in each factor → two places total → 9.189.18.

Step 4: Reconcile with the estimate: 9.189.18 vs 10\approx 10 ✓. Note how the estimate would have caught both classic errors: 91.891.8 (too big) and 0.9180.918 (too small).

Example 2 — 5.46÷0.65.46 \div 0.6: shift, divide, interpret

The context: \$5.46 buys juice at \$0.60 per cup. How many cups?

Step 1: Estimate: \$0.60 a cup, about \$5.50 → roughly 9 cups.

Step 2: Shift both points one place (multiply both by 10): 54.6÷654.6 \div 6.

Step 3: Divide: 54.6÷6=9.154.6 \div 6 = 9.1.

Step 4: Reconcile and interpret: 9.1 vs estimate 9 ✓. In the story: 9 full cups, with a tenth of a cup's worth of money left (6 cents). The division is exact; the story rounds it.

Step 5: Why shifting is legal, said once more: 5.460.6=54.66\frac{5.46}{0.6} = \frac{54.6}{6} — top and bottom both times ten, and a fraction's value survives that.

Example 3 — The unit-price showdown: which detergent wins?

The shelf: Brand A — 1.2 L for \$4.68. Brand B — 0.85 L for \$3.57.

Step 1: Unit price A: 4.68÷1.24.68 \div 1.2. Shift: 46.8÷12=3.9046.8 \div 12 = 3.90 → $3.90 per litre.

Step 2: Unit price B: 3.57÷0.853.57 \div 0.85. Shift twice: 357÷85=4.2357 \div 85 = 4.2 → $4.20 per litre.

Step 3: Verdict: A is cheaper per litre by \$0.30.

Step 4: The sanity checks that catch shifted-point disasters: a unit price near \$4/L should sit BETWEEN the two sticker prices divided by their sizes' neighbourhood — \$39.0/L or \$0.39/L would both scream. Estimates aren't decoration in decimal division; they're the guardrail the moving point demands.

MATERIALS
10×10 decimal grids
Play money
Store flyers
Estimation bracket cards
Practice set (PDF)
WATCH FOR
!"Multiplication makes bigger, division makes smaller" — broken by factors below 1. The grid pictures fix the intuition.
!Decimal points aligned for multiplication as if adding. Points align for ADDITION; multiplication counts places instead.
!In division, only the divisor's point shifted. Both shift together — it's multiplying both by the same ten.