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LESSON PLAN

Multiplication and Division Facts to 100

A
Apothem Team
Grade 6 · Computational Fluency
LESSON AT A GLANCE
Warm-up
5 min
Explore
15 min
Formalize
10 min
Practice
12 min
Exit ticket
3 min

Warm-up

Flash a 60-second "facts sprint" of twelve mixed multiplication and division facts, then ask the honest question: "Which two facts made you pause?" Collect the class's stubborn facts on the board — typically 7×8, 6×7, 48÷6, 9×6.

Today isn't about learning facts from scratch; it's about closing the last gaps and making retrieval automatic enough to support fractions, ratios, and algebra, where a slow fact stalls a whole solution.

Explore

Run a derived-facts workshop on the class's stubborn list: each pair takes one stubborn fact and builds two derivation ropes for it (7×8 = 7×4 doubled = 56; or 5×8 + 2×8 = 40 + 16). Pairs post their ropes and teach them.

Then invert everything: for each multiplication fact posted, students write its two division siblings and one "missing factor" form (7 × ▢ = 56). The wall becomes a map showing every fact family the class once feared, each with a rescue rope attached.

Formalize

Formalize the derivation strategies by name — doubling, halving, adding a group, subtracting a group, splitting through 5 or 10 — and the family structure that makes division free:

a×b=c    c÷a=b    c÷b=aa \times b = c \;\Longleftrightarrow\; c \div a = b \;\Longleftrightarrow\; c \div b = a

The distributive idea underneath every rope, shown once with an array: 7×8=(5+2)×8=5×8+2×87\times8 = (5+2)\times8 = 5\times8 + 2\times8. Students don't need the property's name today — they need to see that splitting a factor splits the rectangle, so the strategy is guaranteed, not lucky.

Practice

Practice in three rounds: a facts ladder (each answer feeds the next problem), missing-factor forms, and five "extend the fact" items (7×8 → 70×8, 7×80, 56÷7, 560÷8).

Exit ticket: your two personal stubborn facts, each written with its full family and your chosen rescue rope.

Exit ticket

Practice in three rounds: a facts ladder (each answer feeds the next problem), missing-factor forms, and five "extend the fact" items (7×8 → 70×8, 7×80, 56÷7, 560÷8).

Exit ticket: your two personal stubborn facts, each written with its full family and your chosen rescue rope.

TIP  Fluency practice works best in short daily bursts with self-tracking, not long weekly sheets. Two minutes a day on a personal stubborn list beats twenty minutes of mixed drill.
WORKED EXAMPLES
Example 1 — Rescue 6 × 7 three ways

Rope 1 — through 5: 6×7=5×7+1×7=35+7=426\times7 = 5\times7 + 1\times7 = 35 + 7 = 42.

Rope 2 — doubling: 6×7=3×76\times7 = 3\times7 doubled =21×2=42= 21 \times 2 = 42.

Rope 3 — through the square: 6×6=366\times6 = 36, one more six → 4242.

Check the family rides along: 42÷6=742 \div 6 = 7, 42÷7=642 \div 7 = 6, 6×=426 \times ▢ = 42.

The standard: within a week, 42 should arrive in under two seconds — but if it ever slips, three ropes are waiting.

Example 2 — Extend one fact across place value: everything 9 × 6 unlocks

Step 1: Anchor: 9×6=549 \times 6 = 54.

Step 2: Scale one factor: 90×6=54090 \times 6 = 540 (ten times as many nines). 9×600=5,4009 \times 600 = 5{,}400.

Step 3: Scale both: 90×60=5,40090 \times 60 = 5{,}400 — one ten from each factor, two tens total.

Step 4: Divisions come free: 540÷9=60540 \div 9 = 60, 5400÷60=905400 \div 60 = 90.

Step 5: The trap case, handled by thinking in tens: 50×6050 \times 60. Fact: 5×6=305\times6 = 30, which already ends in zero; attach the two tens → 3,0003{,}000 (not 300). Count factors of ten; never just "add the zeros."

Example 3 — The remainder tells on you: 58 ÷ 7

Step 1: Hunt the nearest seven-fact below 58: 7×8=567 \times 8 = 56.

Step 2: Quotient 8, remainder 5856=258 - 56 = 2. So 58÷7=858 \div 7 = 8 r 22.

Step 3: The fluency point: this took one retrieval and one subtraction. A student who scans the whole seven-times column (7,14,21,7, 14, 21, \ldots) spends ten times longer — remainder problems are where slow facts become visible.

Step 4: Write the check equation that certifies the answer: 7×8+2=587 \times 8 + 2 = 58 ✓. Quotient-times-divisor-plus-remainder equals the original: the certificate every division carries.

MATERIALS
Fact sprint sheets
Array grid paper
Fact-family triangle cards
Personal tracking cards
Practice set (PDF)
WATCH FOR
!Division treated as a separate memory load from multiplication. The family structure halves the work — insist every fact is stored once, read four ways.
!Derived strategies seen as "cheating" versus memorization. Automaticity is the goal; derivation is the safety net that also deepens structure.
!Zeros mishandled in extensions: 50 × 40 = 200. Count tens as factors: 5×4 = 20, then two tens → 2,000.