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LESSON PLAN

Linear Relations

A
Apothem Team
Grade 7 · Algebra & Patterning
LESSON AT A GLANCE
Warm-up
5 min
Explore
15 min
Formalize
10 min
Practice
12 min
Exit ticket
3 min

Warm-up

Project the pizza-night deal: "Delivery costs \$5 flat, plus \$9 per pizza." Ask three quick questions: cost of 2 pizzas? (23) Of 5? (50) Of ZERO pizzas — just the delivery guy showing up? (\$5 — laughter, but it's the y-intercept being born.)

Build the table together and notice: every extra pizza adds the SAME \$9. Constant change is the signature of LINEAR relations — today they get tables, graphs, and equations, all saying the same thing.

Explore

Representation-quartet lab: each pair takes a scenario (pizza deal; savings starting at \$12 growing \$6/week; a candle 20 cm tall burning 2 cm/h) and produces all four representations — story, table, graph, equation — on one placemat.

Cross-checks with structure: the constant difference in the table IS the coefficient in the equation IS the steepness of the graph; the start value IS the zero-column entry IS where the line meets the vertical axis. The candle adds the decreasing case: negative rate, downhill line, and a meaningful end (height 0 at 10 h — where the model stops).

Formalize

Formalize the linear form and the two parameters' jobs:

y=mx+bm=constant rate of changeb=start value (x=0)y = mx + b \qquad m = \text{constant rate of change} \qquad b = \text{start value } (x = 0)

Reading each representation for mm and bb: table — the per-step difference and the x=0x=0 row; graph — steepness (rise per run) and the vertical-axis crossing; story — the "per" quantity and the flat/starting amount. Fluency is hopping between the four without recomputing from scratch.

Practice

Practice: complete a placemat for a new scenario; extract equations from two tables and one graph; two prediction questions ("when does the candle die?"); one comparison — two phone plans' lines crossing, with the crossover interpreted.

Exit ticket: a table shows x:0,1,2,3y:7,10,13,16x: 0, 1, 2, 3 \to y: 7, 10, 13, 16. Equation? (y=3x+7y = 3x + 7 — and say which number was read from WHICH feature.)

Exit ticket

Practice: complete a placemat for a new scenario; extract equations from two tables and one graph; two prediction questions ("when does the candle die?"); one comparison — two phone plans' lines crossing, with the crossover interpreted.

Exit ticket: a table shows x:0,1,2,3y:7,10,13,16x: 0, 1, 2, 3 \to y: 7, 10, 13, 16. Equation? (y=3x+7y = 3x + 7 — and say which number was read from WHICH feature.)

TIP  Always ask "what does the x = 0 entry MEAN here?" — the intercept has a story-meaning (the flat fee, the starting height) and students who narrate it stop confusing mm with bb.
WORKED EXAMPLES
Example 1 — From table to equation to prediction: the savings account

The table: week 0 → \$12, week 1 → \$18, week 2 → \$24, week 3 → \$30.

Step 1: Rate: each week adds 6 → m=6m = 6 dollars/week.

Step 2: Start: week 0 holds 12 → b=12b = 12. Equation: y=6x+12y = 6x + 12.

Step 3: Predict week 10: y=60+12=72y = 60 + 12 = 72 dollars.

Step 4: Reverse-predict: when does the balance hit $90? 6x+12=906x + 12 = 906x=786x = 78x=13x = 13 weeks.

Step 5: Say the two directions' names: evaluating (plug in xx) answers "how much by then?"; solving (find xx) answers "when do we get there?" One line, both services.

Example 2 — Reading a graph cold: the scuba ascent

The graph: a diver's depth over time — a straight line from (0,30)(0, -30) rising to (6,0)(6, 0).

Step 1: Intercept: at t=0t = 0, depth 30-30 m — the dive starts 30 m down. (b=30b = -30.)

Step 2: Rate from rise-over-run: climbs 30 m in 6 min → m=+5m = +5 m/min.

Step 3: Equation: d=5t30d = 5t - 30.

Step 4: Interrogate it: depth at t=4t = 4? d=10d = -10 m. When does the diver pass 20-20 m? 5t30=205t - 30 = -20t=2t = 2 min.

Step 5: Model boundaries, stated like a pro: past t=6t = 6 the equation predicts positive depth — a flying diver. The LINE continues; the MODEL stops at the surface. Every linear model wears a domain, and graduates of this unit say so unprompted.

Example 3 — Same line, four disguises: prove the table and story match

The story: a print shop charges $3 setup plus $0.75 per poster. The table: x:4,8,12y:6,9,12x: 4, 8, 12 \to y: 6, 9, 12. A student asks whether they describe the same deal.

Step 1: Extract the story's equation directly: y=0.75x+3y = 0.75x + 3.

Step 2: Extract the table's equation: differences — every +4+4 posters adds +3+3 dollars → rate 34=0.75\frac{3}{4} = 0.75 ✓. Back up to x=0x = 0: from (4,6)(4, 6), remove one step: 63=36 - 3 = 3b=3b = 3 ✓.

Step 3: Verdict: same line, y=0.75x+3y = 0.75x + 3 — the table just sampled it at multiples of 4.

Step 4: The subtle skill exposed: the table hid bb (no zero row) and hid mm (steps of 4, not 1) — and both were recoverable by structure. Representations disguise the parameters; they can't destroy them.

MATERIALS
Placemat templates (story/table/graph/equation)
Grid paper
Scenario cards
Practice set (PDF)
WATCH FOR
!mm and bb swapped in equations built from stories. The narrated-intercept habit fixes the binding.
!Graphs drawn by connecting only the plotted dots without extending the pattern — or extended past where the story allows (candle height below 0).
!Non-constant tables force-fitted with a single rate. Check EVERY gap; one uneven step disqualifies linearity.