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LESSON PLAN

Square Roots and Perfect Squares

A
Apothem Team
Grade 7 · Number
LESSON AT A GLANCE
Warm-up
5 min
Explore
15 min
Formalize
10 min
Practice
12 min
Exit ticket
3 min

Warm-up

Hand out 25 square tiles per pair: "Arrange all 25 into a perfect square. Now try 26. Now 36." The 26 attempt fails visibly — a row always sticks out.

Name what worked: 25 and 36 are PERFECT SQUARES (525^2, 626^2), and the side length of the square is the SQUARE ROOT. The tiles make both words literal: the root is the side that grew the square.

Explore

Square-building census: pairs chart every perfect square from 121^2 to 15215^2 and mark them on a number line to 225 — noticing the gaps widen (squares thin out as numbers grow; the gap between consecutive squares is the odd numbers: 3, 5, 7, …).

Then root-trapping: where does 50\sqrt{50} live? Between 49=7\sqrt{49} = 7 and 64=8\sqrt{64} = 8, much nearer 7. Pairs trap 20\sqrt{20}, 90\sqrt{90}, 140\sqrt{140} between consecutive integers and refine one of them to a decimal guess, checked by squaring (4.52=20.254.5^2 = 20.25 — a hair high, so 204.47\sqrt{20} \approx 4.47).

Formalize

Formalize the inverse pair and the trapping method:

n2=n    (n0)49<50<64    7<50<8\sqrt{n^2} = n \;\; (n \ge 0) \qquad 49 < 50 < 64 \;\Rightarrow\; 7 < \sqrt{50} < 8

Squaring and square-rooting undo each other — the same inverse-operation relationship as add/subtract and multiply/divide, extending the family. Vocabulary: radical sign, radicand, perfect square. Calculator roots are approximations for non-perfect squares; the trapped estimate is the sanity check on the calculator, not vice versa.

Practice

Practice: perfect-square retrieval sprint (81\sqrt{81}, 144\sqrt{144}, 169\sqrt{169}); trap four roots between integers with the nearer end named; refine two to one decimal; one applied problem (a square garden of 90 m² — fence length?).

Exit ticket: between which two consecutive whole numbers is 75\sqrt{75}, which is it nearer, and why? (88 and 99; nearer 9 since 75 is nearer 81 than 64.)

Exit ticket

Practice: perfect-square retrieval sprint (81\sqrt{81}, 144\sqrt{144}, 169\sqrt{169}); trap four roots between integers with the nearer end named; refine two to one decimal; one applied problem (a square garden of 90 m² — fence length?).

Exit ticket: between which two consecutive whole numbers is 75\sqrt{75}, which is it nearer, and why? (88 and 99; nearer 9 since 75 is nearer 81 than 64.)

TIP  The squares through 15215^2 (and 20220^2, 25225^2) should be retrieval-fast by week's end — root estimation is only as quick as the square facts underneath it.
WORKED EXAMPLES
Example 1 — Trap and refine 72\sqrt{72}

Step 1: Bracket with neighbouring perfect squares: 64<72<8164 < 72 < 81, so 8<72<98 < \sqrt{72} < 9.

Step 2: Judge position inside the bracket: 72 sits 8 above 64 and 9 below 81 — nearly the midpoint, leaning low. First guess: 8.5.

Step 3: Test by squaring: 8.52=72.258.5^2 = 72.25 — a whisker high. Try 8.49272.088.49^2 \approx 72.08; 8.48271.918.48^2 \approx 71.91. So 728.49\sqrt{72} \approx 8.49.

Step 4: Calculator confirms 8.4853…; our two-step refinement was correct to the displayed precision. The method — bracket, judge, square-test — needs no button and builds the number sense the button hides.

Example 2 — The square dance floor: roots in a real layout

The problem: a square dance floor covers 144 m². The crew needs its side length, the length of edging for the full perimeter, and whether a 13 m banner fits along one side.

Step 1: Side: 144=12\sqrt{144} = 12 m (perfect square — retrieval).

Step 2: Perimeter: 4×12=484 \times 12 = 48 m of edging.

Step 3: Banner: 13 m against a 12 m side — doesn't fit flat. (It would fit on the DIAGONAL — about 1221712\sqrt{2} \approx 17 m — a teaser for the Pythagorean unit next.)

Step 4: The reverse question that checks understanding: "a square floor's perimeter is 60 m — what's its area?" Side =15= 15, area =225= 225 m². Root and square, both directions, inside one context.

Example 3 — A student claims 16+9=25\sqrt{16} + \sqrt{9} = \sqrt{25} "because 16 + 9 = 25"

Step 1: Compute each side honestly: left — 16+9=4+3=7\sqrt{16} + \sqrt{9} = 4 + 3 = 7. Right — 25=5\sqrt{25} = 5. They differ: the claim is false, despite its beautiful coincidence bait.

Step 2: Diagnose the lure: 16+9=2516 + 9 = 25 is TRUE for the radicands; the error is assuming the root function respects addition. Roots respect MULTIPLICATION (16×9=144=12=4×3\sqrt{16 \times 9} = \sqrt{144} = 12 = 4 \times 3 ✓) but not addition.

Step 3: Geometric view of why: gluing a 16-tile square and a 9-tile square makes 25 tiles' worth of area, but not a square shape — you can rearrange into a 5×5, yet the SIDES 4 and 3 never added to 5 in the process; area added, sides didn't.

Step 4: File the general caution: functions don't automatically distribute over addition. This exact error will re-audition in algebra as (a+b)2=a2+b2(a+b)^2 = a^2 + b^2 — same disease, and today's counterexample is the vaccine.

MATERIALS
Square tiles
Number lines to 225
Perfect-square chart
Calculators (for verification round only)
Practice set (PDF)
WATCH FOR
!50\sqrt{50} guessed as 25 ("half of 50") — the root undoes squaring, not doubling. Tiles: a 25-sided square holds 625 tiles.
!Roots of non-perfect squares declared "impossible." They're real numbers between integers — the trap locates them.
!a+b\sqrt{a+b} split as a+b\sqrt{a}+\sqrt{b} (later grades' plague, plantable now): 9+16=5\sqrt{9+16} = 5, but 3+4=73 + 4 = 7. One counterexample, memorized.